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Fix the foreign key definition for the contacts table.

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Mark Crane
2013-09-20 20:13:19 +00:00
parent 3a9a05fb56
commit 798afaf3fe
1 changed files with 3 additions and 1 deletions
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4
app/contacts/app_config.php
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@@ -93,7 +93,9 @@
$apps[$x]['db'][$y]['fields'][$z]['type']['pgsql'] = 'uuid';
$apps[$x]['db'][$y]['fields'][$z]['type']['sqlite'] = 'text';
$apps[$x]['db'][$y]['fields'][$z]['type']['mysql'] = 'char(36)';
$apps[$x]['db'][$y]['fields'][$z]['key']['type'] = 'primary';
$apps[$x]['db'][$y]['fields'][$z]['key']['type'] = 'foreign';
$apps[$x]['db'][$y]['fields'][$z]['key']['reference']['table'] = 'v_contacts';
$apps[$x]['db'][$y]['fields'][$z]['key']['reference']['field'] = 'contact_uuid';
$apps[$x]['db'][$y]['fields'][$z]['description']['en-us'] = '';
$z++;
$apps[$x]['db'][$y]['fields'][$z]['name'] = 'contact_type';